7[5-(4-4x)]+4x=4(8x+2)-1

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Solution for 7[5-(4-4x)]+4x=4(8x+2)-1 equation: 


Simplifying
7[5 + -1(4 + -4x)] + 4x = 4(8x + 2) + -1
7[5 + (4 * -1 + -4x * -1)] + 4x = 4(8x + 2) + -1
7[5 + (-4 + 4x)] + 4x = 4(8x + 2) + -1

Combine like terms: 5 + -4 = 1
7[1 + 4x] + 4x = 4(8x + 2) + -1
[1 * 7 + 4x * 7] + 4x = 4(8x + 2) + -1
[7 + 28x] + 4x = 4(8x + 2) + -1

Combine like terms: 28x + 4x = 32x
7 + 32x = 4(8x + 2) + -1

Reorder the terms:
7 + 32x = 4(2 + 8x) + -1
7 + 32x = (2 * 4 + 8x * 4) + -1
7 + 32x = (8 + 32x) + -1

Reorder the terms:
7 + 32x = 8 + -1 + 32x

Combine like terms: 8 + -1 = 7
7 + 32x = 7 + 32x

Add '-7' to each side of the equation.
7 + -7 + 32x = 7 + -7 + 32x

Combine like terms: 7 + -7 = 0
0 + 32x = 7 + -7 + 32x
32x = 7 + -7 + 32x

Combine like terms: 7 + -7 = 0
32x = 0 + 32x
32x = 32x

Add '-32x' to each side of the equation.
32x + -32x = 32x + -32x

Combine like terms: 32x + -32x = 0
0 = 32x + -32x

Combine like terms: 32x + -32x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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